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(2/3)^(2x^2-13x-7)+(2/3)^(-2x+13x+7)=2
We move all terms to the left:
(2/3)^(2x^2-13x-7)+(2/3)^(-2x+13x+7)-(2)=0
Domain of the equation: 3)^(2x^2-13x-7)!=0
x∈R
Domain of the equation: 3)^(-2x+13x+7)!=0We add all the numbers together, and all the variables
x∈R
(+2/3)^(2x^2-13x-7)+(+2/3)^(11x+7)-2=0
We calculate fractions
(6^(11x+7))/(-13x+3)^(2x^2-7)*3)^(11x+7))+(6^(2x^2-13x-7))/(-13x+3)^(2x^2-7)*3)^(11x+7))-2=0
We add all the numbers together, and all the variables
-13x+(6^(11x+7))/(-13x+3)^(2x^2-7)*3)^(11x+7))+(6^(2x^2-7))/(-13x+3)^(2x^2-7)*3)^(11x+7))-2=0
We calculate fractions
-13x+7))+(6^(2x^2+((6^(11x+7))*(-13x+3)^(2x^2-7)*3)^11x/((-13x+3)^(2x^2-7)*3)^(11x*(-13x+3)^(2x^2-7)*3)^11x-13x+3)^(2x^2-7)*3)^11x/((-13x+3)^(2x^2-7)*3)^(11x*(-13x+3)^(2x^2-7)*3)^11x+(-7))*(=0
We add all the numbers together, and all the variables
-52x+7))+(6^(2x^2+((6^(11x+7))*(-13x+3)^(2x^2-7)*3)^11x/((-13x+3)^(2x^2-7)*3)^(11x*(-13x+3)^(2x^2-7)*3)^11x+3)^(2x^2-7)*3)^11x/((+3)^(2x^2-7)*3)^(11x*(+3)^(2x^2-7)*3)^11x+(-7))*(=0
We calculate fractions
-52x+7))+(6^(2x^2+3)^(2x^2+3)^(2x^2-7)*3)^(11x*(+3)^(2x^2-7)*3)^11x+(-7))*(+(((6^(11x+7))*(-13x+3)^(2x^2-7)*3)^11x*(()/(((-13x+3)^(2x^2-7)*3)^(11x*(-13x+3)^(2x^2-7)*3)^11x*(()+(-26x-7)*3)^11x*(3^(2x^2-7)*3)^(11x*3^(2x^2-7)*3)^11x)/(((-13x+3)^(2x^2-7)*3)^(11x*(-13x+3)^(2x^2-7)*3)^11x*(()=0
We can not solve this equation
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